5.2 The line

The simplest geometric structure (apart from the point) is the line. To describe a line p completely we need to know a point A which is contained by the line and a direction of the line, i.e. a non-zero vector a. The line p then consists of all points with coordinates

(5.2)(x,y)=A+ta,tR.

The number t is called a parameter as it parametrises the points on the line. Note that if we bound the set of possible values of t we get only parts of the line. For instance, for t0,+) we get a ray with the initial point A and direction a, whereas for t0,1 we get a line segment with A and A+a as its end points. This way of describing a line, i.e. by an equation (5.2), is often called the parametric equation of a line.

An alternative way of describing a line is this. A line consists of all points with coordinates (x,y) which satisfy the linear equation of a line

(5.3)ax+by+c=0.

Constants a,b,c are parameters of the line. In equation (5.3), the symbols x and y represent unknowns. A point (α,β) is contained in the given line if and only if after substituting α for x and β for y into (5.3) we get a valid equality (0=0). Let's analyze in more detail the line p described by equation

(5.4)x2y+1=0.

The point (1,2) does not lie on p because after substituting to (5.4) we get 2=0 which is not true. On the contrary, (1,0) and (0,1/2) after substituting give 0=0 and so they do lie on the line. Two points are sufficient to plot a line.

We assume that the reader knows how to convert a parametric equation of a line to its linear equation and vice versa.

Question 5.1

Convert the parametric equation of a line into a linear equation: (x,y)=(1,2)+(2t,t), tR.

Show answer

x+2y5=0.

Question 5.2

Convert the linear equation into a parametric equation for 3x2y+1=0.

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(x,y)=(1,1)+t(2,3).

Question 5.3

Construct a linear equation of a line containing points (1,3) and (2,4).

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7xy10=0.